An Arithmetic progression which consists of the sequence & the terms except the 1st can be obtained by adding 1 numbe! r to its preceding number. Arithmetic progression is denoted as the arrangement of 2 consecutive numbers, the progression which is constant. Sequence of numbers such that the difference of any 2 successive members of the sequence is a constant
If a, b, c are in A.P then prove that (a–c)2 = 4(b2 – ac)
Solution: a, b, c are in A.P
⇒ b – a = c – b = common difference
⇒ 2b = a + c
⇒ 4b2 = a2 + 2ac + c2 (Squaring both sides)
⇒ 4b2 – 4ac = a2 – 2ac + c2 ( Subtracting 4ac on both sides)
⇒ 4(b2 – ac) = (a – c)2 ( Taking 4 common)
In our next blog we shall learn about math practice test Free I hope the above explanation was useful.Keep reading and leave your comments.Free geometry help
No comments:
Post a Comment