Tuesday, August 31, 2010

arithmetic progression

Let us learn about arithmetic progression

An Arithmetic progression which consists of the sequence & the terms except the 1st can be obtained by adding 1 numbe! r to its preceding number. Arithmetic progression is denoted as the arrangement of 2 consecutive numbers, the progression which is constant. Sequence of numbers such that the difference of any 2 successive members of the sequence is a constant

If a, b, c are in A.P then prove that (a–c)2 = 4(b2 – ac)

Solution: a, b, c are in A.P

b – a = c – b = common difference

2b = a + c

4b2 = a2 + 2ac + c2 (Squaring both sides)

4b2 – 4ac = a2 – 2ac + c2 ( Subtracting 4ac on both sides)

4(b2 – ac) = (a – c)2 ( Taking 4 common)

In our next blog we shall learn about math practice test Free I hope the above explanation was useful.Keep reading and leave your comments.

Free geometry help

No comments:

Post a Comment